Module 1: Now You Try IV

Let

$LaTeX: \vec{v} = \begin{pmatrix} 1 \\ 3 \end{pmatrix} \mbox{ and } \vec{u} = \begin{pmatrix} -1 \\ 2 \end{pmatrix}.$ $\vec{v} = \begin{pmatrix} 1 \\ 3 \end{pmatrix} \mbox{ and } \vec{u} = \begin{pmatrix} -1 \\ 2 \end{pmatrix}.$

1. Compute $LaTeX: \|\vec{u}\|$ $\|\vec{u}\|$

Solution:

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$LaTeX: \|\vec{v} \| = \sqrt{(-1)^2 + 2^2} = \sqrt{5}.$

$\|\vec{v} \| = \sqrt{(-1)^2 + 2^2} = \sqrt{5}.$