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Review 2: Now You Try III
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Review 2: Now You Try III
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Review 2: Now You Try III
Compute:
1.
∫
π
/
2
0
cos
x
d
x
Solution:
▶ Show
∫
π
2
0
cos
x
d
x
=
sin
x
|
π
2
0
=
sin
(
π
2
)
−
sin
(
0
)
=
1.
2.
∫
t
0
cos
x
d
x
Solution:
▶ Show
∫
t
0
cos
x
d
x
=
sin
x
|
t
0
=
sin
(
t
)
−
sin
(
0
)
=
sin
(
t
)
.
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Review 2: Definite versus Indefinite Integral
Review 3: Introduction