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Review 2: Now You Try II
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Review 2: Now You Try II
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Review 2: Now You Try II
Compute:
1.
∫
2
1
(
x
−
1
)
d
x
Solution:
▶ Show
\int_1^2\left( x-1\right)\; dx=\left(\frac{x^2}{2}-x\right) \Big |_1^2=\left(\frac{2^2}{2}-2\right)-\left(\frac{1^2}{2}-1\right)
2.
\int_0^{\frac{\pi}{4}} \sec^2 \theta\; d\theta
Solution:
▶ Show
\int_0^{\frac{\pi}{4}} \sec^2 \theta\; d\theta=\left(\tan \theta\right) \Big |_0^{\frac{\pi}{4}}=\tan(\frac{\pi}{4})-\tan(0)=1.
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Review 2: Definite Integrals
Review 2: Definite versus Indefinite Integral